How do you solve for the current flow through R1 with a voltage of 6 volts, R1 of 12, and R2 of 6?

To determine the current flow through the resistor R1 with a voltage applied across the circuit, the first step is to understand the configuration of the resistors and how they relate to the total circuit voltage.

Assuming R1 and R2 are in series, the total resistance in the circuit can be calculated by adding R1 and R2 together. Given R1 is 12 ohms and R2 is 6 ohms, the total resistance (R_total) is:

R_total = R1 + R2 = 12Ω + 6Ω = 18Ω.

Next, using Ohm's Law, which states that Voltage (V) equals Current (I) times Resistance (R), we can manipulate the formula to solve for current (I):

I = V / R_total.

With a voltage of 6 volts applied across the series of resistors, we apply this to our total resistance:

I = 6V / 18Ω = 0.333A.

Now, since we want the current flowing through R1, we need to remember that the same current flows through all components in a series circuit. Therefore, the current through R1 is also 0.333A.

To find the voltage drop across R