In a transformer with a primary rating of 7,200 volts and a secondary rating of 480 volts, what is the secondary current flow when the primary current is 8 amperes?

To determine the secondary current flow in a transformer, you can use the principle of power conservation between the primary and secondary sides of the transformer. The formula that applies is:

[ V_p \times I_p = V_s \times I_s ]

where:

• ( V_p ) is the primary voltage,

• ( I_p ) is the primary current,

• ( V_s ) is the secondary voltage, and

• ( I_s ) is the secondary current.

Given the primary voltage of 7,200 volts, the primary current of 8 amperes, and a secondary voltage of 480 volts, we can rearrange the formula to solve for the secondary current ( I_s ):

[ I_s = \frac{V_p \times I_p}{V_s} ]

Substituting the known values:

[ I_s = \frac{7,200 , \text{volts} \times 8 , \text{amperes}}{480 , \text{volts}} ]

Calculating the numerator:

[ 7,200 \times 8 = 57,600 ]

Now divide by the secondary voltage:

[ I_s = \frac{57,